If two different integers out of first 10 positive integers are to be chosen, what is the probability that one of the integer is square of the other?
Correct Answer : a ) 2/45Explanation :
The first ten positive integers are 1, 2, 3, ..... 10
Now to select two integers out of these with one as square of other, there are two possible situations: (2, 4) and (3, 9)
So, the total favourable outcomes will be = 2
Total possible ways of selecting two integers out of 10 is 10C2 = 10!/(8! x 2!) = 90/2 = 45
Probability of getting one of the integer as square of the other = 2/45
Hence, (A) is the correct answer.
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