Geometry Practice Question for SSC CGL, SSC CHSL, Banking 26 October 2020

Question of The Day26-10-2020

Three sides of a quadrilateral PQRS are PQ = 11 cm, QR = 9 cm and RS = 12 cm. If diagonal PR and QS intersect each other at 900, then what will be the length of side SP?

Answer

Correct Answer : d ) 7.6

Explanation :

Depicting the given information

In ∆ POQ

Using Pythagoras theorem

PQ² = OP² + OQ² ……. (1)

In ∆ QOR

Using Pythagoras theorem

QR² = OQ² + OR² ……. (2)

In ∆ ROS

Using Pythagoras theorem

RS² = OR² + OS² ……. (3)

In ∆ POS

Using Pythagoras theorem

PS² = OP² + OS² ……. (4)

Adding equation 1, 2, 3 and 4

PQ² + QR² + RS² + PS² = 2 (OP² + OQ² + OR² + OS²)

From equation 1 and 3

⇒ PQ² + QR² + RS² + PS² = 2 (PQ² + RS²)

⇒ PQ² + RS² = QR² + PS²

Now, putting the value given in question

11² + 9² = 1²² + SP²

⇒ SP² = 121 + 81 – 144 = 58

⇒SP=\(\sqrt58\) ~ 7.6

Hence, (d) is the correct answer.

Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA etc.

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