The speed of Ravi is 18 km/hr and that of Teja is 9 km/hr. If the length of the circular track is 200 m, then in 4 minutes, how many times will they meet each other?

Question of The Day19-10-2020

Ravi and Teja participate in a race that is going to be held on a circular track. The speed of Ravi is 18 km/hr and that of Teja is 9 km/hr. If the length of the circular track is 200 m, then in 4 minutes, how many times will they meet each other?

Answer

Correct Answer : a ) 3 times

Explanation :

We know,

Distance=speed×time

⇒Time taken by Ravi to cover 1 round of 200m track=\(200\over5\)=40 sec

Similarly,

⇒Time taken by Teja to cover 1 round of 200m track=\(200 \over 2.5\)=80 sec

Now, time taken by both of them to meet each other for 1^st time = LCM (40, 80) = 80 seconds

We can say that, after every 80 seconds Ravi and Teja will meet each other.

Thus, in a time span of 4 minutes, i.e., 240 seconds Ravi and Teja will meet each other

⇒\(240 \over 80\)=3 times

Hence, (a) is the correct answer.

Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA etc.

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