# Find the value of Y in the given below question: Where,

2019-09-09 | Team PendulumEdu

If $$x-\frac{1}{x}=7$$ then the value of $$Y=\frac{(7x^2-7)}{(3x^2+7x-3)}$$ is

Options:

A. 2/5

B. 7/4

C. 3

D. 9/2

Solution:

Consider the expression given  in the question and simplify it, we get

$$=\frac{(7x^2-7)}{(3x^2+7x-3)}$$

$$=\frac{7x(x-\frac{1}{x})}{x(3x+7-\frac{3}{x}) }$$

$$=\frac{7x(x-\frac{1}{x})}{x(3(x-\frac{1}{x})+7)}$$

Substituting the given value of $$(x-\frac{1}{x})$$ in the simplified expression, we get

$$=\frac{(7\times 7)}{(3\times ×7+7)}$$

$$=\frac{49}{28}=\frac{7}{4}$$

Hence, (B) is the correct answer.

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