# Find the value of Y in the given below question: Where,

2019-09-09 | Team PendulumEdu

If \(x-\frac{1}{x}=7\) then the value of \(Y=\frac{(7x^2-7)}{(3x^2+7x-3)}\) is

**Options: **

**A.** 2/5

**B. **7/4

**C.** 3

**D. **9/2

**Solution:**

Consider the expression given in the question and simplify it, we get

\(=\frac{(7x^2-7)}{(3x^2+7x-3)}\)

\(=\frac{7x(x-\frac{1}{x})}{x(3x+7-\frac{3}{x}) }\)

\(=\frac{7x(x-\frac{1}{x})}{x(3(x-\frac{1}{x})+7)} \)

Substituting the given value of \((x-\frac{1}{x})\) in the simplified expression, we get

\(=\frac{(7\times 7)}{(3\times ×7+7)}\)

\(=\frac{49}{28}=\frac{7}{4}\)

Hence, **(B)** is the correct answer.

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