Two positions of the same dice are shown below. There are different numbers printed on each face of the dice. If a number printed on one of the faces is ‘1’, then what will be the least sum of digits on opposite faces?

## Answer

Correct Answer : b ) 10

Explanation :Consider the given positions of dice

To find out the numbers opposite to faces on the dice, we should follow the following steps:

- First, find the common number/symbol on both the positions of dice
- Then, starting from the common number move in the clockwise direction in both the dice
- While moving in clockwise direction note down the other numbers/symbols
- Lastly, compare the numbers/symbols thus obtained. The next numbers after the common number in both the positions of the dice will be on the opposite faces of the dice.

**NOTE:** The above logic cannot be applied on the positions of the dice on which more than one face has common number or symbols. For such cases the non-common numbers will be opposite to each other.

Therefore, analyzing position I and position II of dice we can say that there is ‘9’ common in both the positions of dice

So,

For position I:

The sequence of the numbers by the above logic will be

9, 12, 5

For position II:

The sequence of the numbers by the above logic will be

9, 6, 7

Now, from the above logic, we can say that

12 is opposite to 6

5 is opposite to 7

According to the question as there is ‘1’ printed on one face of the dice so,

1 is opposite to 9

Therefore, sum of the digits on opposite faces will be

9 + 1 ⇒ 10

12 + 6 ⇒ 18

5 + 7 ⇒ 12

Thus, the least sum will be ⇒ 10

Hence, (b) is the correct answer.

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