Two positions of the same dice are shown below. There are different numbers printed on each face of the dice. If a number printed on one of the faces is ‘1’, then what will be the least sum of digits on opposite faces?
Answer
Correct Answer : b ) 10
Explanation :Consider the given positions of dice
To find out the numbers opposite to faces on the dice, we should follow the following steps:
- First, find the common number/symbol on both the positions of dice
- Then, starting from the common number move in the clockwise direction in both the dice
- While moving in clockwise direction note down the other numbers/symbols
- Lastly, compare the numbers/symbols thus obtained. The next numbers after the common number in both the positions of the dice will be on the opposite faces of the dice.
NOTE: The above logic cannot be applied on the positions of the dice on which more than one face has common number or symbols. For such cases the non-common numbers will be opposite to each other.
Therefore, analyzing position I and position II of dice we can say that there is ‘9’ common in both the positions of dice
So,
For position I:
The sequence of the numbers by the above logic will be
9, 12, 5
For position II:
The sequence of the numbers by the above logic will be
9, 6, 7
Now, from the above logic, we can say that
12 is opposite to 6
5 is opposite to 7
According to the question as there is ‘1’ printed on one face of the dice so,
1 is opposite to 9
Therefore, sum of the digits on opposite faces will be
9 + 1 ⇒ 10
12 + 6 ⇒ 18
5 + 7 ⇒ 12
Thus, the least sum will be ⇒ 10
Hence, (b) is the correct answer.
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