A milkman has 3 jugs of 8 liter, 5 liter and 3 liter capacity and jug of 8 liter capacity is full with milk. If he wishes to give 4 liters of milk to a customer and he can only use the 3 jugs, then the number of minimum steps in which he can do that are:
Correct Answer : c ) 6Explanation :
Let us take the jugs in the sequence 8L – 5L – 3L
As, in the start only 8L jug is full so we can denote our sequence in terms of milk in each container as 8L – 0L – 0L
Step 1: In the first step we will transfer the milk from 8L jug to the 5L jug
Thus, milk in each container as per the sequence will be 3L – 5L – 0L
Step 2: In the second step we will transfer the milk from 5L jug to the 3L jug.
Thus, milk in each container as per the sequence will be 3L – 2L – 3L
Step 3: Now, from the 3L jug we will transfer all milk into 8L jug. Now, 8L capacity jug will have 6L milk.
Thus, milk in each container as per the sequence will be 6L – 2L – 0L
Step 4: Now, from 5L capacity jug we will transfer the milk into 3L capacity jug. As, 5L capacity jug have only 2L milk so after transfer milk in each container as per the sequence will be 6L – 0L – 2L
Step 5: Now, transfer 5L milk from the 8L capacity jug into 5L capacity jug.
After the transfer milk in each container as per the sequence will be 1L – 5L – 2L
Step 6: Now, transfer milk from 5L capacity jug into 3L capacity jug. As, in 3L capacity jug there is only space for 1L milk thus,
After the transfer milk in each container as per the sequence will be 1L – 4L – 3L
Now, milkman have 4L milk in his 5L capacity jug so, he can now give 4L milk to his customer.
To do so milkman has to do 6 steps.
Hence, (c) is the correct answer.
Such type of question is asked in various government exams like RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA, UP SI etc.
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