What is the ratio of compound interest earned on a certain amount at the rate of 10% for 3rd year and 5th year?
Answer
Correct Answer : c ) 100 : 121
Explanation :According to the question:
Rate of interest = 10%
Time1 = 3 years
Time2 = 5 years
We know that,Compound interst CI=\({P[(1+{r\over100})^n}-1]\),
Here, P = principal amount, r = rate of interest and n = time
⇒CI of 3rd year=\({P[(1+{10\over100})^3}-1]-{P[(1+{10\over100})^2}-1]\)
⇒CI of 3rd year=\({P(1+{10\over100})^2}(1+{10\over100}-1)\)
⇒CI of 3rd year=\({P(1+{1\over10})^2}({1\over10})\)
Similarly, CI of 5th year =\({P(1+ {1\over10})^4}({1\over10})\)
Thus, the required ratio=\({P({11\over10})^2}({1\over10}) : {P({11\over10})^4}({1\over10}) \)
=102 :112
= 100 : 121
Hence, (c) is the correct answer.
Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA etc.
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