Find the area of the triangle formed by the straight line x – y = 2 , x + 2y = 8 and y- axis.
Answer
Correct Answer : a ) 12 sq. un.
Explanation :According to the question
Straight lines are x – y = 2 ……..(1)
x + 2y = 8 …….(2)
x = 0 ……..(3)
Firstly, we need to find the points at which lines intersect, as these points will be the vertices of the triangle.
Subtracting eq(1) form eq (2)
⇒ 3y = 6
⇒ y = 2
⇒ x – y = 2
⇒ x = 2 + 2
⇒ x = 4
⇒ lines 1 and 2 intersect at A (4, 2)
⇒ Lines 1 and 3 intersect at C (0, -2)
⇒ Lines 2 and 3 intersect at B (0, 4)
As shown in figure
Area of △ABC
Height AD = 4 units
Base (BC) = 4 + 2
⇒ 6 units
Area of triangle=\({1 \over 2}\)*base*height
⇒\({1 \over 2}*6*4\)
⇒ 12 sq. units
Hence, (a) is the correct answer.
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