A 2 m wide pathway is developed parallel to the rectangular park’s boundary. If the breadth of the park is 15 m and the area of the park is 300 m2, then what will be the area of the pathway?
Answer
Correct Answer : a ) 124 m2
Explanation :Let us assume the length of the park will be x m.
According to the given information, the schematic of the park can be shown as
As, given breadth of park = 15 m
And, Area of park = 300 m2
Length * breadth = 300 m2
15x = 300
x = 20 m
Now,
Length of the pathway inside boundary will be ⇒ 20 – 2 – 2 = 16 m
And, breadth of the pathway inside boundary will be ⇒ 15 – 2 – 2 = 11 m
Thus,
Area of the pathway = area of park – shaded area
= 300 – (16 x 11)
= 124 m2
Hence, (A) is the correct answer.
Questions related to Mensuration are asked in Quantitative Aptitude section of different exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, etc. Try and attempt free mock tests at PendulumEdu.
One can also clear all exam related doubts through PendulumEdu’s One-to-One session.
Comments