If 7th and 17th terms of an arithmetic progression are 15 and 27, then what will be the sum of the first 18 terms of the series?
Answer
Correct Answer : d ) 324
Explanation :We know that
nth term of an arithmetic progression is given as
an = a + (n – 1) d
where, a is the first term, d is the common difference
According to the question
a7 = a + 6d = 15 ……. (1)
a17 = a + 16d = 27 ……. (2)
Comparing equation (1) and (2) we get
a = 7.8 and d = 1.2
Thus,
Sum of an arithmetic progression is given as= \({n \over 2} (2a+(n-1)d)\)
Thus, sum of first 18 terms of the series will be
= \({18 \over 2} (2*7.8+(18-1)*1.2)\)
= 324
Hence, (d) is the correct answer.
Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA etc.
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