Question of The Day05-12-2019

There are two stations A and B, having two parallel rail lines between them. Train X and Train Y travel between the two stations. When the trains travel in the same direction, train X takes 5 minutes to cross train Y. When the trains travel in the opposite direction, it took them 1 minute to cross each other. Find the speed of Train X and Train Y, respectively, if the length of each train is 200m.

Correct Answer : a ) 4 m/s and 8/3 m/s

Explanation :

Let us assume the speeds of train X and train Y are S1 and S2, respectively.

According to the question, each train is 200m long, so both trains have to travel 400m individually to cross each other.

Case I: When trains moving in the same direction

Given, Time = 5 min = 300 sec

Now, Relative speed = S1 – S2

As we know, Distance = Speed x Time

Thus,

300 x (S1 – S2) = 400 …………. (1)

Case II: When trains moving in the opposite direction

Given, Time = 1 min = 60 sec

Now, Relative speed = S1 + S2

As we know, Distance = Speed x Time

Thus,

60 x (S1 + S2) = 400………….. (2)

Solving equation (1) and (2)

We get,

S1 = 4 m/s

S2 = 8/3 m/s

Hence, (A) is the correct answer.

Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, etc.

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