A and B starts working on a project such that they work on it in alternate months starting from B. The work gets completed in \(19 {1 \over 5}\) months. If A alone can complete the project in 23 months, then in how many months B alone can complete the work?
Answer
Correct Answer : b ) \(16 {2 \over 3}\)
Explanation :As total work gets completed in \(19 {1 \over 5}\) months and B started doing the work for first month
So, Number of months B had worked upon the project = 10 months
And, Number of months A had worked upon the project will be
\(=19 {1 \over 5} -10=19-10+15=9 {1 \over 5}\) months
A alone can complete the project in 23 months
Part of work completed by A in 1 month = \({1 \over 23}\)
Part of work completed by A in 915 month = \( {1 \over 23}*(9 {1 \over 5})={1 \over 23} * {46 \over 5}={2 \over 5}\)
Now, remaining work = \(1- {2 \over 5}= {3 \over 5}\)
Therefore, \(( {3 \over 5})\)th of the work is completed by B in 10 months
So, total work is completed by B in=\(10* {5 \over 3}= {50 \over 3}=16 {2 \over 3}\)months
Hence, (b) is the correct answer.
Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS etc.
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