If 4 men and 20 children can do the work in 9 days and 15 children and a men can complete the same work in 15 days. Efficiency of Men is what percent more than the efficiency of Children?
Answer
Correct Answer : a ) 114.28%
Explanation :According to the question
Let the efficiency of men be ‘M’ and children be ‘C’
We know that
By MHD formula
\({M1*E1*D1*H1 \over W1}={M2*E2*D2*H2 \over W2}\)
Where, M, E, D, H and W are Number of person, efficiency, days, Hours and work Respectively.
Substituting the values
⇒\({(4*M+20*C)*9 \over 1}={(1*M+15*C)*15 \over 1}\)
⇒ (4M + 20C) * 3 = (M + 15C)*5
⇒ 12M + 60C = 5M + 75C
⇒ 7M = 15 C
⇒\({M \over C}={15 \over 7}\)
Efficiency of men more than Children = 15 – 7 = 8
⇒Required Percentage=\({8 \over 7}*100\)
⇒ 114.28%
Hence, (a) is the correct answer.
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