What is the shortest distance between origin and the line 12x + 5y = 26?
Answer
Correct Answer : b ) 2
Explanation :The shortest distance from a point P (x1, y1) to the straight-line having equation Ax + By + c = 0 will be the length of the perpendicular drawn from point P to the line Ax + By + C = 0
Distance=\({|Ax_1+By_1+C| \over \sqrt{A^2+B^2}}\)
Thus, shortest distance between origin (0, 0) and line 12x + 5y – 26 = 0 will be
Distance=\({|0+0-26| \over \sqrt{12^2+5^2}} ={26 \over 13}\)=2 unit
Hence, (b) is the correct answer.
Such type of questions from Coordinate Geometry is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA etc.
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