Question of The Day14-09-2020

A man is 5 times more efficient than a boy. If boy started working and did work for 20 days and then replaced by man. After that man worked for 5 days and \(9 \over 10\) part of the work gets completed. In how many days a man alone can finish the remaining work?


Correct Answer : c ) \(1\) day

Explanation :

According to the question,

Man is 5 times more efficient than a boy

Let us assume efficiency of man is 5 units and that of boy is 1 unit

We know,

Work done = time taken × efficiency

Now, boy started the work and did work for 20 days

So, amount of work done by boy = 1 × 20 = 20 units

Man worked for 5 days

Thus, amount of work done by man = 5 × 5 = 25 units

Thus, total work done by boy and man = 20 + 25 = 45 units

According to question, 9/10 part of the work gets completed

\({9 \over 10}\)of total work=45 units

\({1 \over 10}\)of total work=5 units

Therefore, time taken by man to compete the 5 units of remaining work will be

\({5 \over efficiency \ of \ man}={5 \over 5}=1\)day

Hence, (c) is the correct answer.

Such type of question is asked in various government exams like SSC CGL, SSC MTS, SSC CPO, SSC CHSL, RRB JE, RRB NTPC, RRB GROUP D, RRB OFFICER SCALE-I, IBPS PO, IBPS SO, RRB Office Assistant, IBPS Clerk, RBI Assistant, IBPS RRB OFFICER SCALE 2&3, UPSC CDS, UPSC NDA, UP SI etc.

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