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Question of The Day24-10-2019

Arrange the following in ascending order

\( \sqrt[5]{(2)^{390}} < \sqrt{(9)^{65}} < \sqrt[3]{(7)^{117}}\)

Answer

Correct Answer : c ) \( \sqrt[5]{(2)^{390}} < \sqrt{(9)^{65}} < \sqrt[3]{(7)^{117}}\)

Explanation :

According to the law of surds

\(\sqrt[m]{\sqrt[n]{\sqrt[o]{(((x)^{p})^{q})^{r}}}}\)can be written as  \(x^{(\frac{P*q*r}{m*n*o})}\)

Thus,

\(\sqrt[5]{(2)^{390}}=2^{\frac{390}{5}}=2^{78}..............1\)

Similarly,

\(\sqrt{(9)^{65}}=9^{\frac{65}{2}}=3^{65}..............2\)

Similarly,

\(\sqrt[3]{(7)^{117}}=7^{\frac{117}{3}}=7^{39}..............3\)

Now, equating the powers in equation 1, 2, and 3, we get

\({(2)^{78}} =>{(64)^{13}} \)

\({(3)^{65}} => {(243)^{13}}\)

\({(7)^{39}} => {(343)^{13}}\)

Therefore, the correct order will be

\({(64)^{13}} < {(243)^{13}} < {(343)^{13}}\)

\(\sqrt[5]{(2)^{390}} < \sqrt{(9)^{65}} < \sqrt[3]{(7)^{117}}\)

Hence, (C) is the correct answer.

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