What will be the wrong number in the given number series, given that the other numbers follows a certain pattern?

17.11, 19.22, 21.44, 23.66, 25.88, 27.10, 30.32

## Answer

Correct Answer : c ) 27.10

Explanation :Consider the given series

17.11, 19.22, 21.44, 23.66, 25.88, 27.10, 30.32

The logic for the above series can be explained as

17.11 = 17 + 0.11

19.22 = 17 + 2 + 0.11*2

21.44 = 17 + 4 + 0.11*4

23.66 = 17 + 6 + 0.11*6

25.88 = 17 + 8 + 0.11*8

**17 + 10 + 0.11*10 = 28.10 ≠ 27.10**

30.32 = 17 + 12 + 0.11*12

Thus, 27.10 is the wrong term in the given series

Hence, (**C**) is the correct answer.

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Who among the following was referred to as “The Father of the Indian Unrest” by the British authorities?

## Answer

Correct Answer : b ) Bal Gangadhar Tilak

Explanation :Bal Gangadhar Tilak was born on 23rd July 1856 in the Ratnagiri district of Maharashtra. He was one among the extremist leader in the group ‘**Lal Bal Pal’**. He was one of the freedom fighters who throughout his life advocated strongly for *Purna Swaraj*. He was given the title of ‘Lokmanya’, literal meaning accepted by the people. He was called “The father of the Indian Unrest” by the British officials.

He was one of the main proponents of expanding the ** Swadeshi** and the

**movement to every part of the country. He also founded the All India Home Rule League in 1916-18. He had been tried for sedition charges many times by the British and was finally given a sentence of 6 years to be spent in Mandalay jail.**

*Boycott*He died on 1st August 1920at the age of 62 in Bombay. He is remembered for his famous slogan in Marathi- “*Swaraj is my birthright and I shall have it*”.

**Hence, b is the correct answer.**

Renowned personalities that contributed to the Indian Freedom struggle are important from the exam point of view. Questions related to this topic are asked in various exams like UPSC CSE, UPSC CDS, State PSC, SSC CGL, SSC CHSL, SSC MTS, etc. One can try and attempt our free mock tests at PendulumEdu and keep oneself updated regarding the latest exam pattern.

**What will be the total surface area of the symmetrical pyramid having a square base with an area of 576 \( m^2\) and height 5 m?**

## Answer

Correct Answer : a ) ** A)** \({1200 m^2}\)

Given:

Height (H) = 5 m

Area of square base =\(576 m^2\)

So, Side of the square, a = \( \sqrt{576} \) = 24 m

Now,

The lateral height of the triangle, L

L = \(\sqrt{H^2+{(\frac{a}{2}})^2}\)

L = \(\sqrt{5^2+{(\frac{24}{2}})^2}\)

L = 13m

There are 4 symmetrical triangles in the pyramid so, the total surface area of the pyramid is

= 4 x (area of triangles) + area of base

= \(4*(\frac{1}{2}*base*height)+576\)

*=*\(4*(\frac{1}{2}*24*13)+576\)

*=* 624 + 576

= \(1200 m^2\)

Hence, (a) is the correct answer.

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